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Dinosaur

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Joined: 12/08/2011
Location: Australia
Posts: 311

Posted: 10:47pm 07 Apr 2019

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Hi All

Testing a "cape" for the Baglebone Black.
It has 20 N Channel Fet's as outputs and 8 opto couplers as Inputs.
The board is designed to handle about 20 Amps at 24 Vdc.
So basically I can drive high current loads (Stepper motors etc) direct.
The Fet's are STU85N3LH5. RDs of 0.005 ohm.

It all works well except at power up of the BBB, all the outputs go to 3.3vdc
and thus turn all the 24 vdc outputs ON.

Anyway, decided on a new approach.
Firstly an E-Stop decides if the outputs should be allowed ON.
But people forget to reset the E-Stop, so not foolproof.
OK, so lets use an output to enable the Supply voltage, however that output is
already ON when you turn the power ON. That's when I dreamt up the circuit below.

Taking advantage of the fact that the outputs are at 3.3vdc , I use it to drive one Fet
to pull the other one Off. As soon as the BBB has powered up, and I have initialised
the outputs, the 24 VDC rail will be allowed through to the 20 O/P's.

My doubt (and that is why I am posting) is if all of the other 20 outputs are off,
the voltage rail above the 20 outputs will sit at 24 vdc.
In fact it will always sit at about 24 vdc.

Should the 1M Ohm resistor be connected to ground or the Source leg (Power rail to 20 o/p's)
Will this circuit even work ?
Problem with loading pdf and jpeg snipit not good resolution.
Top R = 2.2K Lower R = 1 M Ohm
Bottom Fet is driven by O/P.

Regards

Edited by Dinosaur 2019-04-09

Regards
Hervey Bay Qld.

wiseguy

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Joined: 21/06/2018
Location: Australia
Posts: 1156

Posted: 05:52am 08 Apr 2019

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Circuit seems ok to me at first glance and should work fine - you have used the issue against itself to effect a cure. I think to be more technically correct 1M resistor should go to ground not the FETs source. Otherwise with no loads there will be a voltage measured at the LEDs (sneak path through 1M resistor) that might be annoying.
I like off to be OFF.

If at first you dont succeed, I suggest you avoid sky diving....
Cheers Mike

Dinosaur

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Joined: 12/08/2011
Location: Australia
Posts: 311

Posted: 02:11am 12 Apr 2019

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Hi All

Am awaiting my board blanks to test the above question, but another "issue" has drawn
my attention.

Up to about 20kHz the rise time is acceptable with only slight rounding at the top,
however at 40 kHz the rounding becomes significant where eventually the peak voltage starts to suffer. The Fall time remains unaffected.

Not sure if I will ever need anything to be switched at that freq, but worth pursuing.

The Gate threshold voltage is specified between 1 to 2.5 v with 1.8v typical.
The Beaglebone black has 3.3 vdc outputs, and so that is the max voltage I will
get at the gate. There are no resistors between the cpu output and the gate.
Turn On time is specified at 6-14 nSec.

My question:
If I drive the gate at 5vdc, will that improve the rise time, and thus extend
the usable freq.?
Tried to find a mosfet with lower Gate threshold voltage , but current capacity
then drops as well.

I can post a waveform if the explanation above is insufficient.

Regards

Regards
Hervey Bay Qld.

tinyt
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Joined: 12/11/2017
Location: United States
Posts: 438

Posted: 12:16pm 12 Apr 2019

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How about changing the Startup FETN with an NPN bjt. I think they turn on at 0.6V. You have to add a series resistor between the base and the BBB O/P. Will probably need another resistor between the base and GND.Edited by tinyt 2019-04-13

Dinosaur

Guru

Joined: 12/08/2011
Location: Australia
Posts: 311

Posted: 12:25am 03 May 2019

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Hi All

Just an update to my circuit above.
tinyt I played around with some transistors I had (2N2222) but could not get the N Channel to to turn on fully.
I think a lot has to do with the N Channel liking to sink the load in the Drain leg.
All 20 of my outputs are in the Drain and deliver the full 24 vdc to the load.
The best I could get was 22.3 vdc.

Anyhow after a lot of trial and error, I concluded that the P Channel is the ideal
candidate because it likes to supply the load in the Drain leg.
And that is the purpose of this, to supply power to all the loads.

I tried dozens of ways to drive the P channel with a N channel, bit in the end the opto
was the best solution.

So for anyone else contemplating this the circuit below.

Regards

EDIT: The part numbers are: P-Channel FQPF47P06 , N Channel x 20 = GK1CL509, Opto VOM618AEdited by Dinosaur 2019-05-04

Regards
Hervey Bay Qld.

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